-1/2(x-3)^2-5

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Solution for -1/2(x-3)^2-5 equation: 


x in (-oo:+oo)

(-1/2)*(x-3)^2-5 = 0

-1/2*(x-3)^2-5 = 0

-1/2*(x-3)^2-5 = 0

3*x-1/2*x^2-19/2 = 0

3*x-1/2*x^2-19/2 = 0

3*x-1/2*x^2-19/2 = 0

DELTA = 3^2-(-19/2*(-1/2)*4)

DELTA = -10

DELTA < 0

1 = 0

1 = 0

x belongs to the empty set

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